Q:

The product of binomial and a trinomial is x^3+3x^2-x+2x^2+6x-2.

Accepted Solution

A:
Answer: x = -2 or x = sqrt(13)/2 - 3/2 or x = -3/2 - sqrt(13)/2Step-by-step explanation:Solve for x: x^3 + 5 x^2 + 5 x - 2 = 0 The left hand side factors into a product with two terms: (x + 2) (x^2 + 3 x - 1) = 0 Split into two equations: x + 2 = 0 or x^2 + 3 x - 1 = 0 Subtract 2 from both sides: x = -2 or x^2 + 3 x - 1 = 0 Add 1 to both sides: x = -2 or x^2 + 3 x = 1 Add 9/4 to both sides: x = -2 or x^2 + 3 x + 9/4 = 13/4 Write the left hand side as a square: x = -2 or (x + 3/2)^2 = 13/4 Take the square root of both sides: x = -2 or x + 3/2 = sqrt(13)/2 or x + 3/2 = -sqrt(13)/2 Subtract 3/2 from both sides: x = -2 or x = sqrt(13)/2 - 3/2 or x + 3/2 = -sqrt(13)/2 Subtract 3/2 from both sides: Answer:  x = -2 or x = sqrt(13)/2 - 3/2 or x = -3/2 - sqrt(13)/2